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| 型号： | LTC3602EFE#PBF |
| 厂商： | Linear Technology |
| 文件页数： | 14/20页 |
| 文件大小： | 0K |
| 描述： | IC REG BUCK SYNC ADJ 16TSSOP |
| 标准包装： | 95 |
| 类型： | 降压（降压） |
| 输出类型： | 可调式 |
| 输出数： | 1 |
| 输出电压： | 0.6 V ~ 9.5 V |
| 输入电压： | 4.5 V ~ 10 V |
| PWM 型： | 电流模式，混合 |
| 频率 - 开关： | 1MHz |
| 电流 - 输出： | 2.5A |
| 同步整流器： | 是 |
| 工作温度： | -40°C ~ 85°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 16-TSSOP（0.173"，4.40mm）裸露焊盘 |
| 包装： | 管件 |
| 供应商设备封装： | 16-TSSOP-EP |
| 产品目录页面： | 1335 (CN2011-ZH PDF) |
LTC3602
APPLICATIONS INFORMATION
Thermal Considerations
In most applications, the LTC3602 does not dissipate much
heat due to its high ef?ciency. But, in applications where the
LTC3602 is running at high ambient temperature with low
supply voltage and high duty cycles, such as in dropout,
the heat dissipated may exceed the maximum junction
temperature of the part. If the junction temperature reaches
approximately 150°C, both power switches will be turned
off and the SW node will become high impedance.
To prevent the LTC3602 from exceeding the maximum
junction temperature, the user will need to do some thermal
analysis. The goal of the thermal analysis is to determine
whether the power dissipated exceeds the maximum
junction temperature of the part. The temperature rise is
given by:
T R = (P D ) ? ( θ JA )
where P D is the power dissipated by the regulator and θ JA
is the thermal resistance from the junction of the die to
the ambient temperature.
The junction temperature, T J , is given by:
Checking Transient Response
The regulator loop response can be checked by looking
at the load transient response. Switching regulators take
several cycles to respond to a step in load current. When
a load step occurs, V OUT immediately shifts by an amount
equal to Δ I LOAD ?(ESR), where ESR is the effective series
resistance of C OUT . Δ I LOAD also begins to charge or dis-
charge C OUT , generating a feedback error signal used by the
regulator to return V OUT to its steady-state value. During
this recovery time, V OUT can be monitored for overshoot
or ringing that would indicate a stability problem. The I TH
pin external components and output capacitor shown in the
front page application will provide adequate compensation
for most applications.
Design Example
As a design example, consider using the LTC3602 in
an application with the following speci?cations: V IN =
8.4V, V OUT = 3.3V, I OUT(MAX) = 2.5A, I OUT(MIN) = 100mA,
f= 1MHz. Because ef?ciency is important at both high and
low load current, Burst Mode operation will be utilized.
First, calculate the timing resistor:
T J = T A + T R
where T A is the ambient temperature.
As an example, consider the LTC3602 in dropout at an
R OSC =
1 . 15 ? 10 11
1 MHz
– 10 k = 105 k
3.3V ?
? ( ) ( ) ? ?
L = ?? ?? ? ? 1– ? = 2μH
3.3V ?
( ? 1MHz ) ( 2.2μH ) ? ? 8 .4V ?
input voltage of 8V, a load current of 2.5A and an ambi-
ent temperature of 70°C. From the Typical Performance
graph of Switch Resistance, the R DS(ON) of the top switch
at 70°C is approximately 120mΩ. Therefore, power dis-
sipated by the part is:
P D = (I LOAD2 )(R DS(ON) ) = (2.5A) 2 (120mΩ) = 0.75W
For the TSSOP package, the θ JA is 38°C/W. Thus the junc-
tion temperature of the regulator is:
T J = 70°C + (0.75W)(38°C/W) = 98.5°C
which is below the maximum junction temperature of
125°C.
Next, calculate the inductor value for about 40% ripple
current at maximum V IN :
? 3.3V ? ?
1MHz 1A 8 .4V ?
Using a 2.2μH inductor results in a maximum ripple cur-
rent of:
? 3.3V ? ?
Δ I L = ?? ?? ? ? 1– ? = 0.91A
C OUT will be selected based on the ESR that is required
to satisfy the output voltage ripple requirement and the
bulk capacitance needed for loop stability. In this applica-
tion, a tantalum capacitor will be used to provide the bulk
3602fb
14
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