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| 型号： | MAX15039ETG+T |
| 厂商： | Maxim Integrated Products |
| 文件页数： | 15/19页 |
| 文件大小： | 0K |
| 描述： | IC REG BUCK SYNC ADJ 6A 24TQFN |
| 产品培训模块： | Lead (SnPb) Finish for COTS Obsolescence Mitigation Program |
| 标准包装： | 2,500 |
| 类型： | 降压（降压） |
| 输出类型： | 可调式 |
| 输出数： | 1 |
| 输出电压： | 0.6 V ~ 4.95 V |
| 输入电压： | 2.9 V ~ 5.5 V |
| PWM 型： | 电压模式 |
| 频率 - 开关： | 500kHz ~ 2MHz |
| 电流 - 输出： | 6A |
| 同步整流器： | 是 |
| 工作温度： | -40°C ~ 85°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 24-WFQFN 裸露焊盘 |
| 包装： | 带卷 (TR) |
| 供应商设备封装： | 24-TQFN-EP（4x4） |
6A, 2MHz Step-Down Regulator
with Integrated Switches
Compensation Design
The power transfer function consists of one double pole
and one zero. The double pole is introduced by the
inductor L and the output capacitor C O . The ESR of the
output capacitor determines the zero. The double pole
and zero frequencies are given as follows:
The above equations are based on the assumptions
that C1 >> C2 and R3 >> R2 are true in most applica-
tions. Placements of these poles and zeros are deter-
mined by the frequencies of the double pole and ESR
zero of the power transfer function. It is also a function
of the desired close-loop bandwidth. The following sec-
2 π x L x C O x ? O
? R O + R L ?
f P 1 _ LC = f P 2 _ LC =
1
? R + ESR ?
?
tion outlines the step-by-step design procedure to cal-
culate the required compensation components for the
MAX15039. When the output voltage of the MAX15039
is programmed to a preset voltage, R3 is internal to the
IC and R4 does not exist (Figure 3b).
f Z _ ESR =
1
2 π x ESR x C O
When externally programming the MAX15039 (Figure
3a), the output voltage is determined by:
where R L is equal to the sum of the output inductor’s DCR
(DC resistance) and the internal switch resistance,
R DS(ON) . A typical value for R DS(ON) is 20m Ω (low-side
MOSFET) and 26m Ω (high-side MOSFET). R O is the output
or:
R 4 =
0 . 6 × R 3
( V OUT ? 0 . 6 )
( for V OUT > 0 . 6 V )
load resistance, which is equal to the rated output voltage
divided by the rated output current. ESR is the total equiv-
alent series resistance of the output capacitor. If there is
R 4 =
( V REFIN × R 3 )
( V OUT ? V REFIN )
more than one output capacitor of the same type in paral-
lel, the value of the ESR in the above equation is equal to
that of the ESR of a single output capacitor divided by the
total number of output capacitors.
The high switching frequency range of the MAX15039
allows the use of ceramic output capacitors. Since the
ESR of ceramic capacitors is typically very low, the fre-
quency of the associated transfer function zero is higher
than the unity-gain crossover frequency, fC, and the zero
if using an external V REFIN , and V OUT > V REFIN .
For a 0.6V output, or for V OUT = V REFIN , connect an
8.06k Ω resistor from FB to V OUT . The zero-cross fre-
quency of the close-loop, f C , should be between 10%
and 20% of the switching frequency, f S . A higher zero-
cross frequency results in faster transient response.
Once f C is chosen, C1 is calculated from the following
equation:
V IN
2 x π x R 3 x ( 1 + L ) × f C
cannot be used to compensate for the double pole creat-
ed by the output filtering inductor and capacitor. The dou-
ble pole produces a gain drop of 40dB/decade and a
phase shift of 180°. The compensation network error
amplifier must compensate for this gain drop and phase
C 1 =
1 . 5625 x
V P ? P
R
R O
f Z 1 _ EA =
f Z 2 _ EA =
1 L x C O x ( R O + ESR )
+ R
R L O
shift to achieve a stable high-bandwidth closed-loop sys-
tem. Therefore, use type III compensation as shown in
Figures 3 and 4. Type III compensation possesses three
poles and two zeros with the first pole, f P1_EA , located at
zero frequency (DC). Locations of other poles and zeros
of the type III compensation are given by:
1
2 π × R 1 × C 1
1
2 π × R 3 × C 3
where V P-P is the ramp peak-to-peak voltage (1V typ).
Due to the underdamped nature of the output LC dou-
ble pole, set the two zero frequencies of the type III
compensation less than the LC double-pole frequency
to provide adequate phase boost. Set the two zero fre-
quencies to 80% of the LC double-pole frequency.
Hence:
R 1 = x
0 . 8 x C 1
f P 3 _ EA =
1
2 π × R 1 × C 2
C 3 =
1
0 . 8 x R 3
x
L x C O x ( R O + ESR )
R L + R O
f P 2 _ EA =
1
2 π × R 2 × C 3
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|---|---|
| MAX15039EVKIT+ | 功能描述:电源管理IC开发工具 6A 2MHz Step-Down w/Integrated Switch RoHS:否 制造商:Maxim Integrated 产品:Evaluation Kits 类型:Battery Management 工具用于评估:MAX17710GB 输入电压: 输出电压:1.8 V |
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| MAX1503YETJ | 制造商:Rochester Electronics LLC 功能描述: 制造商:Maxim Integrated Products 功能描述: |
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