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| 型号： | MAX1567ETL+ |
| 厂商： | Maxim Integrated Products |
| 文件页数： | 31/35页 |
| 文件大小： | 0K |
| 描述： | IC DGTL CAM PWR-SUP 6CH 40TQFN |
| 产品培训模块： | Lead (SnPb) Finish for COTS Obsolescence Mitigation Program |
| 标准包装： | 50 |
| 应用： | 控制器，数字式相机 |
| 输入电压： | 0.7 V ~ 5.5 V |
| 输出数： | 7 |
| 输出电压： | 1.25 V ~ 5 V |
| 工作温度： | -40°C ~ 85°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 40-WFQFN 裸露焊盘 |
| 供应商设备封装： | 40-TQFN-EP（6x6） |
| 包装： | 管件 |
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Six-Channel, High-Efficiency, Digital
Camera Power Supplies
The C C R C zero is then used to cancel the f P pole, so:
R C = R LOAD x C OUT x V OUT / [(2V OUT - V IN ) x C C ]
AUX Step-Up, Continuous Inductor Current
Continuous inductor current can sometimes improve
boost efficiency by lowering the ratio between peak
inductor current and output current. It does this at the
expense of a larger inductance value that requires larger
size for a given current rating. With continuous inductor-
current boost operation, there is a right-half-plane zero,
Z RHP , at the following:
Z RHP = (1 - D) 2 x R LOAD / (2 π x L)
where (1 - D) = V IN / V OUT (in a boost converter).
There is a complex pole pair at the following:
f 0 = V OUT / [2 π x V IN (L x C OUT ) 1/2 ]
If the zero due to the output capacitance and ESR is
less than 1/10 the right-half-plane zero:
Z COUT = 1 / (2 π x C OUT x R ESR ) < Z RHP / 10
Then choose C C so the crossover frequency f C occurs
at Z COUT . The ESR zero provides a phase boost at
crossover:
C C = (V IN / V RAMP ) (V FB / V OUT ) [g M / (2 π x Z COUT )]
Choose R C to place the integrator zero, 1 / (2 π x R C x
C C ), at f 0 to cancel one of the pole pairs:
R C = V IN (L x C OUT ) 1/2 / (V OUT x C C )
If Z COUT is not less than Z RHP / 10 (as is typical with
ceramic output capacitors) and continuous conduction
is required, then cross the loop over before Z RHP and f 0 :
f C < f 0 / 10, and f C < Z RHP / 10
In that case:
C C = (V IN / V RAMP ) (V FB / V OUT ) (g M / (2 π x f C ))
Place:
1 / (2 π x R C x C C ) = 1 / (2 π x R LOAD x C OUT ), so that
R C = R LOAD x C OUT / C C
Or, reduce the inductor value for discontinuous operation.
MAX1567 AUX2 Inverter Compensation,
Discontinuous Inductor Current
If the load current is very low ( ≤ 40mA), discontinuous
current is preferred for simple loop compensation and
freedom from duty-cycle restrictions on the inverter
input-output ratio. To ensure discontinuous operation,
the inductor must have a sufficiently low inductance to
fully discharge on each cycle. This occurs when:
L < [V IN / (|V OUT | + V IN )] 2 R LOAD / (2f OSC )
A discontinuous current inverter has a single pole at the
following:
f P = 2 / (2 π x R LOAD x C OUT )
Choose the integrator cap so the unity-gain crossover,
f C , occurs at f OSC / 10 or lower. Note that for many AUX
circuits that do not require fast transient response, it is
often acceptable to overcompensate by setting f C at
f OSC / 20 or lower.
C C is then determined by the following:
C C = [V IN / (K 1/2 x V RAMP )] [V REF / (V OUT + V REF )] [g M /
(2 π x f C )]
where K = 2L x f OSC / R LOAD , and V RAMP is the internal
slope-compensation voltage ramp of 1.25V.
The C C R C zero is then used to cancel the f P pole, so:
R C = (R LOAD x C OUT ) / (2C C )
MAX1567 AUX2 Inverter Compensation,
Continuous Inductor Current
Continuous inductor current may be more suitable for
larger load currents (50mA or more). It improves effi-
ciency by lowering the ratio between peak inductor cur-
rent and output current. It does this at the expense of a
larger inductance value that requires larger size for a
given current rating. With continuous inductor-current
inverter operation, there is a right-half-plane zero,
Z RHP , at:
Z RHP = [(1 - D) 2 / D] x R LOAD / (2 π x L)
where D = |V OUT | / (|V OUT | + V IN ) (in an inverter).
There is a complex pole pair at:
f 0 = (1 - D) / (2 π (L x C) 1/2 )
If the zero due to the output-capacitor capacitance and
ESR is less than 1/10 the right-half-plane zero:
Z COUT = 1 / (2 π x C OUT x R ESR ) < Z RHP / 10
Then choose C C such that the crossover frequency f C
occurs at Z COUT . The ESR zero provides a phase boost
at crossover:
C C = (V IN / V RAMP ) [V REF / (V REF + |V OUT |)] [g M /
(2 π x Z COUT )]
Choose R C to place the integrator zero, 1 / (2 π x R C x
C C ), at f 0 to cancel one of the pole pairs:
R C = (L x C OUT ) 1/2 / [(1 - D) x C C ]
If Z COUT is not less than Z RHP / 10 (as is typical with
ceramic output capacitors) and continuous conduction
is required, then cross the loop over before Z RHP and f 0 :
f C < f 0 /10, and f C < Z RHP / 10
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相关代理商/技术参数 |
参数描述 |
|---|---|
| MAX1567ETL+ | 功能描述:PMIC 解决方案 6Ch Digital Camera Power Supply RoHS:否 制造商:Texas Instruments 安装风格:SMD/SMT 封装 / 箱体:QFN-24 封装:Reel |
| MAX1567ETL+T | 功能描述:PMIC 解决方案 6Ch Digital Camera Power Supply RoHS:否 制造商:Texas Instruments 安装风格:SMD/SMT 封装 / 箱体:QFN-24 封装:Reel |
| MAX1567ETL-T | 功能描述:PMIC 解决方案 RoHS:否 制造商:Texas Instruments 安装风格:SMD/SMT 封装 / 箱体:QFN-24 封装:Reel |
| MAX1567EVKIT | 制造商:Maxim Integrated Products 功能描述:6-CHANNEL HIGH EFFICIENCY DIGITAL CAMERA POWE - Bulk |
| MAX1567SUMEVKIT | 制造商:Maxim Integrated Products 功能描述:6-CHANNEL HIGH EFFICIENCY DIGITAL CAMERA POWE - Bulk |
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