参数资料
型号: MAX5099ATJ+
厂商: Maxim Integrated Products
文件页数: 21/27页
文件大小: 0K
描述: IC REG BUCK SYNC ADJ DL 32TQFN
产品培训模块: Lead (SnPb) Finish for COTS
Obsolescence Mitigation Program
标准包装: 60
类型: 降压(降压)
输出类型: 可调式
输出数: 2
输出电压: 0.8 V ~ 17.1 V
输入电压: 4.5 V ~ 19 V
PWM 型: 电压模式
频率 - 开关: 200kHz ~ 2.2MHz
电流 - 输出: 1A,2A
同步整流器:
工作温度: -40°C ~ 125°C
安装类型: 表面贴装
封装/外壳: 32-WFQFN 裸露焊盘
包装: 管件
供应商设备封装: 32-TQFN-EP(5x5)
Dual, 2.2MHz, Automotive Synchronous Buck
Converter with 80V Load-Dump Protection
f C ≤ SW
G M =
×
×
V ( ESR + 2 π × f × L ) × V
R F = OSC C OUT OUT
C F =
Calculate the temperature rise of the die using the fol-
lowing equation:
T J = T C x (P T x θ JC )
where θ JC is the junction-to-case thermal impedance of
the package equal to +1.7°C/W. Solder the exposed
pad of the package to a large copper area to minimize
the case-to-ambient thermal impedance. Measure the
temperature of the copper area near the device at a
worst-case condition of power dissipation, and use
+1.7°C/W as θ JC thermal impedance.
Compensation
The MAX5099 provides an internal transconductance
amplifier with its inverting input and its output available
for external frequency compensation. The flexibility of
external compensation for each converter offers wide
selection of output filtering components, especially the
output capacitor. For cost-sensitive applications, use
high-ESR aluminum electrolytic capacitors; for compo-
nent size-sensitive applications, use low-ESR tantalum,
polymer, or ceramic capacitors at the output. The high
switching frequency of the MAX5099 allows the use of
ceramic capacitors at the output.
Choose all the passive power components that meet
the output ripple, component size, and component cost
requirements. Choose the small-signal components for
the error amplifier to achieve the desired closed-loop
bandwidth and phase margin. Use a simple pole-zero
pair (Type II) compensation if the output capacitor ESR
zero frequency is below the unity-gain crossover
frequency (f C ). Type III compensation is necessary
when the ESR zero frequency is higher than f C or when
compensating for a continuous-mode boost converter
that has a right-half-plane zero.
2) Select the unity-gain crossover frequency:
f
20
If the f ZERO,ESR is lower than f C and close to f LC , use a
Type II compensation network where R F C F provides a
midband zero f MID,ZERO , and R F C CF provides a high-
frequency pole.
3) Calculate modulator gain G M at the crossover
frequency.
V IN ESR 0 . 8
V OSC ESR + ( 2 π × f C × L OUT ) V OUT
where V OSC is a peak-to-peak ramp amplitude equal
to 1V.
The transconductance error-amplifier gain is:
G E/A = g M x R F
The total loop gain at f C should be equal to 1:
G M x G E/A = 1
or
0 . 8 × V IN × g M × ESR
4) Place a zero at or below the LC double-pole:
1
2 π × R F × f LC
5) Place a high-frequency pole at f P = 0.5 x f SW .
Use procedure 1 to calculate the compensation
network components when f ZERO,ESR < f C .
Buck Converter Compensation
Procedure 1 (See Figure 3)
1) Calculate the f ZERO,ESR and LC double-pole
frequencies:
C CF =
V OUT
R 1
C F
( 2 π × 0 . 5 f SW × R F × C F ) ? 1
f ZERO , ESR =
f LC =
1
2 π × ESR × C OUT
1
2 π L OUT × C OUT
R 2
FB_
V REF
-
+
g M
R F
COMP_
C F
Figure 3. Type II Compensation Network
C CF
______________________________________________________________________________________
21
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