参数资料
型号: MAX8833ETJ+T
厂商: Maxim Integrated Products
文件页数: 15/20页
文件大小: 0K
描述: IC REG BUCK ADJ 3A DL 32TQFN
产品培训模块: Lead (SnPb) Finish for COTS
Obsolescence Mitigation Program
标准包装: 2,500
类型: 降压(降压)
输出类型: 可调式
输出数: 2
输出电压: 0.6 V ~ 3.24 V
输入电压: 2.35 V ~ 3.6 V
PWM 型: 电压模式
频率 - 开关: 1MHz ~ 2MHz
电流 - 输出: 3A
同步整流器:
工作温度: -40°C ~ 85°C
安装类型: 表面贴装
封装/外壳: 32-WFQFN 裸露焊盘
包装: 带卷 (TR)
供应商设备封装: 32-TQFN-EP(5x5)
Dual, 3A, 2MHz Step-Down Regulator
2 π × f C × R 4 × ? 1 + L ?
f Z 2 _ EA =
1
2 π × R 4 × C 11
C 9 =
2 . 5 × V IN
? R ?
? R O ?
f P 2 _ EA =
f P 3 _ EA =
1
2 π × R 7 × C 10
1
2 π × R 8 × C 11
where V IN is the input voltage in volts, f C is the
crossover frequency in Hertz, R4 is the upper feedback
resistor (in ohms), R L is the sum of the inductor resis-
tance and the internal switch on-resistance, and R O is
the output load resistance (V OUT /I OUT ).
Due to the underdamped nature of the output LC double
These equations are based on the assumptions that C9
>> C10, and R4 >> R8, which are true in most applica-
tions. Placement of these poles and zeros is deter-
mined by the frequencies of the double pole and ESR
zero of the power stage transfer function. It is also a
pole, set the two zero frequencies of the type III com-
pensation less than the LC double-pole frequency to
provide adequate phase boost. Set the two zero fre-
quencies to 80% of the LC double-pole frequency.
Hence:
function of the desired closed-loop bandwidth. Figure 5
shows the pole zero cancellations in the type III com-
pensation design.
R 7 =
1
0 . 8 × C 9
×
L × C O × ( R O + ESR )
R L + R O
The following section outlines the step-by-step design
procedure to calculate the required compensation com-
ponents. Begin by setting the desired output voltage as
C 11 =
1
0 . 8 × R 4
×
L × C O × ( R O + ESR )
R L + R O
described in the Setting the Output Voltage section.
The crossover frequency f C (or closed-loop, unity-gain
bandwidth of the regulator) should be between 10%
Set the third compensation pole, f P3_EA , at f Z_ESR ,
which yields:
and 20% of the switching frequency, f S . A higher
crossover frequency results in a faster transient
response. Too high of a crossover frequency can result
R 8 =
C O × ESR
C 11
in instability. Once f C is chosen, calculate C9 (in
farads) from the following equation:
OPEN-LOOP GAIN
COMPENSATION TRANSFER FUNCTION
THIRD POLE
DOUBLE POLES
SECOND POLE
POWER-STAGE TRANSFER FUNCTION
FIRST AND SECOND ZEROS
FREQUENCY
Figure 5. Pole Zero Cancellations in Compensation Design
______________________________________________________________________________________
15
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