参数资料
型号: SC4508AMLTRT
厂商: Semtech
文件页数: 15/21页
文件大小: 0K
描述: IC REG CTRLR BST INV PWM 12-MLPQ
标准包装: 1
PWM 型: 电流模式
输出数: 1
频率 - 最大: 1.5MHz
占空比: 97%
电源电压: 2.7 V ~ 15 V
降压:
升压:
回扫:
反相:
倍增器:
除法器:
Cuk:
隔离:
工作温度: -40°C ~ 125°C
封装/外壳: 12-VQFN 裸露焊盘
包装: 标准包装
产品目录页面: 1358 (CN2011-ZH PDF)
其它名称: SC4508AMLDKR
SC4508A
POWER MANAGEMENT
Application Information (Cont.)
assumptions, the controller parameters are determined
as follows:
100
100
C 2 =
R 2 =
g m kR o
2 π f c
R o C o
C 2
h
20 ? log ( T ( f )
0
)
76.67
53.33
30
and
6.67
C 3 =
100 1 . 10 1 . 10 1 . 10 1 . 10
10 ? 10
R oesr C o
R 2
For example, if V o =3.3V, I o =2A, f s =300kHz, C o =100uF,
R oesr =10m ? , R s =35m ?, one can calculate that::
V o
R o =
= 1 . 65 ?
I o
? 40
? 85
16.67
40
1
85
1
10
3 4 5
f 5
6
and
h =
0 . 5
V o
= 0 . 152
180
π
arg ( T ( f ) )
87
89
91
k =
1
8 ? R S
= 3 . 57
93
100 1 . 10 1 . 10 1 . 10 1 . 10
10 × 10
If the converter crossover frequency is set around 1/10
of the switching frequency, f c = 30kHz, the controller
parameters then can be calculated as:
? 95 95
1
1
10
3 4 5
f 5
6
C 2 =
g m kR o
2 π f c
h ≈ 23 . 6 nF
Figure 8. The loop transfer function Bode plot of the
buck example.
R 2 =
= 7 . 5 k ?
C 3 =
≈ 134 pF
( 1 ?
)( 1 +
)
: = G vc ( s ) = k
V o ( s ) 1 ? D s zRHP s z 1
R o
V c ( s )
1 +
where, g m is the error amplifier transconductance gain
(100 μ ? ? 1 ).
If we use C 2 = 22 nF,
R o C o
C 2
use R 2 = 7.5k ? .
It is further calculated that:
R oesr C o
R 2
use C 3 = 120pF. The Bode plot of the loop transfer
function (magnitude and phase) is shown in Figure 8.
It is clear that the resulted crossover frequency is about
30 kHz with phase margin 91 o .
For buck-boost converter, a simplified equivalent circuit
model of the buck converter with current mode control
is shown in Figure 9 and the transfer function from the
voltage error amplifier output (v c ) to the converter output
(v o ) is:
s s
1 + D s
s p 1
? 2007 Semtech Corp.
15
www.semtech.com
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