参数资料
型号: TPA3005D2PHPR
厂商: Texas Instruments
文件页数: 5/31页
文件大小: 0K
描述: IC AMP AUDIO PWR 6W STER 48TQFP
标准包装: 1
类型: D 类
输出类型: 2 通道(立体声)
在某负载时最大输出功率 x 通道数量: 6W x 2 @ 8 欧姆
电源电压: 8.5 V ~ 18 V
特点: 差分输入,短路保护和热保护,关机
安装类型: 表面贴装
供应商设备封装: 48-HTQFP(7x7)
封装/外壳: 48-TQFP 裸露焊盘
包装: 标准包装
产品目录页面: 877 (CN2011-ZH PDF)
配用: 296-18924-ND - EVAL MODULE FOR TPA3005D2
其它名称: 296-17058-6
0 V
12 V
+12 V
Current
OUTP
OUTN
Differential
Voltage
Across
Load
0 V
12 V
+12 V
Current
OUTP
OUTN
Differential
Voltage
Across
Load
Output = 0 V
Output > 0 V
www.ti.com
SLOS427A – MAY 2004 – REVISED AUGUST 2010
Figure 17. The TPA3005D2 Output Voltage and Current Waveforms Into an Inductive Load
Efficiency: LC Filter Required With the Traditional Class-D Modulation Scheme
The main reason that the traditional class-D amplifier needs an output filter is that the switching waveform results
in maximum current flow. This causes more loss in the load, which causes lower efficiency. The ripple current is
large for the traditional modulation scheme, because the ripple current is proportional to voltage multiplied by the
time at that voltage. The differential voltage swing is 2 x VCC, and the time at each voltage is half the period for
the traditional modulation scheme. An ideal LC filter is needed to store the ripple current from each half cycle for
the next half cycle, while any resistance causes power dissipation. The speaker is both resistive and reactive,
whereas an LC filter is almost purely reactive.
The TPA3005D2 modulation scheme has little loss in the load without a filter because the pulses are short and
the change in voltage is VCC instead of 2 x VCC. As the output power increases, the pulses widen, making the
ripple current larger. Ripple current could be filtered with an LC filter for increased efficiency, but for most
applications the filter is not needed.
An LC filter with a cutoff frequency less than the class-D switching frequency allows the switching current to flow
through the filter instead of the load. The filter has less resistance than the speaker, which results in less power
dissipation, therefore increasing efficiency.
Effects of Applying a Square Wave Into a Speaker
Audio specialists have advised for years not to apply a square wave to speakers. If the amplitude of the
waveform is high enough and the frequency of the square wave is within the bandwidth of the speaker, the
square wave could cause the voice coil to jump out of the air gap and/or scar the voice coil. A 250-kHz switching
frequency, however, does not significantly move the voice coil, as the cone movement is proportional to 1/f2 for
frequencies beyond the audio band.
Copyright 2004–2010, Texas Instruments Incorporated
13
Product Folder Link(s): TPA3005D2
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