参数资料
型号: TPS54140DGQR
厂商: TEXAS INSTRUMENTS INC
元件分类: 稳压器
英文描述: SWITCHING REGULATOR, 2500 kHz SWITCHING FREQ-MAX, PDSO10
封装: GREEN, PLASTIC, MSOP-10
文件页数: 25/46页
文件大小: 1778K
代理商: TPS54140DGQR
ORIPPLE
ESR
RIPPLE
V
R
I
<
(35)
Vout
(Vin max
Vout)
Icorms =
12
Vin max
Lo
sw
-
(36)
Catch Diode
2
(Vin max
Vout)
Iout
Vd
Cj
sw
Vin
+ Vd
Pd =
+
2
Vin max
-
(37)
Input Capacitor
www.ti.com .............................................................................................................................................................................................. SLVS889 – OCTOBER 2008
The TPS54140 requires an external catch diode between the PH pin and GND. The selected diode must have a
reverse voltage rating equal to or greater than Vinmax. The peak current rating of the diode must be greater than
the maximum inductor current. The diode should also have a low forward voltage. Schottky diodes are typically a
good choice for the catch diode due to their low forward voltage. The lower the forward voltage of the diode, the
higher the efficiency of the regulator will be.
Typically, the higher the voltage and current ratings the diode has, the higher the forward voltage will be. Since
the design example has an input voltage up to 18V, a diode with a minimum of 20V reverse voltage will be
selected.
For the example design, the B220A Schottky diode is selected for its lower forward voltage and it comes in a
larger package size which has good thermal characteristics over small devices. The typical forward voltage of the
B220A is 0.50 volts.
The diode must also be selected with an appropriate power rating. The diode conducts the output current during
the off-time of the internal power switch. The off-time of the internal switch is a function of the maximum input
voltage, the output voltage, and the switching frequency. The output current during the off-time is multiplied by
the forward voltage of the diode which equals the conduction losses of the diode. At higher switch frequencies,
the ac losses of the diode need to be taken into account. The ac losses of the diode are due to the charging and
discharging of the junction capacitance and reverse recovery. Equation 37 is used to calculate the total power
dissipation, conduction losses plus ac losses, of the diode.
The B220A has a junction capacitance of 120pF. Using Equation 37, the selected diode will dissipate 0.632
Watts. This power dissipation, depending on mounting techniques, should produce a 16°C temperature rise in
the diode when the input voltage is 18V and the load current is 1.5A.
If the power supply spends a significant amount of time at light load currents or in sleep mode consider using a
diode which has a low leakage current and slightly higher forward voltage drop.
The TPS54140 requires a high quality ceramic, type X5R or X7R, input decoupling capacitor of at least 3
F of
effective capacitance and in some applications a bulk capacitance. The effective capacitance includes any dc
bias effects. The voltage rating of the input capacitor must be greater than the maximum input voltage. The
capacitor must also have a ripple current rating greater than the maximum input current ripple of the TPS54140.
The input ripple current can be calculated using Equation 38.
The value of a ceramic capacitor varies significantly over temperature and the amount of dc bias applied to the
capacitor. The capacitance variations due to temperature can be minimized by selecting a dielectric material that
is stable over temperature. X5R and X7R ceramic dielectrics are usually selected for power regulator capacitors
because they have a high capacitance to volume ratio and are fairly stable over temperature. The output
capacitor must also be selected with the dc bias taken into account. The capacitance value of a capacitor
decreases as the dc bias across a capacitor increases.
For this example design, a ceramic capacitor with at least a 20V voltage rating is required to support the
maximum input voltage. Common standard ceramic capacitor voltage ratings include 4V, 6.3V, 10V, 16V, 25V,
50V or 100V so a 25V capacitor should be selected. For this example, two 2.2
F, 25V capacitors in parallel have
been selected. Table 1 shows a selection of high voltage capacitors. The input capacitance value determines the
input ripple voltage of the regulator. The input voltage ripple can be calculated using Equation 39. Using the
design example values, Ioutmax = 1.5 A, Cin = 4.4
F, sw = 1200 kHz, yields an input voltage ripple of 71 mV
and a rms input ripple current of 0.701A.
Copyright 2008, Texas Instruments Incorporated
31
Product Folder Link(s): TPS54140
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