参数资料
型号: 18448
英文描述: Microprocessor Family CPU Thermal Management Application Note? 126KB (PDF)
中文描述: 微处理器系列CPU散热管理应用笔记? 126KB(PDF格式)
文件页数: 5/10页
文件大小: 126K
代理商: 18448
AMD
4
CPU Thermal Management
Figure 4. Heat Flow Path
Figure 5. Thermal Resistance Paths
(Schematic Representation)
Figure 6. Derating Curve
Heat Transfer
Any discussion of heat transfer should begin with a brief
overview of how heat is transferred. There are three
mechanisms by which heat may be transferred: convec-
tion, radiation, and conduction.
Convection involves the transfer of heat by the mixing
of fluid. It is the primary process for heat transfer from
a solid to a liquid or gas in contact with it. The rate of
convection heat flow is mainly a function of surface area,
position of the solid in contact with the fluid, the fluids
velocity and properties, and gravity force.
Thermal radiation is heat transferred by electromagnet-
ic radiation. It exists always, but is the only means of
heat transfer between entities separated by a vacuum.
Heat transfer by conduction involves the transfer of ki-
netic energy from one molecule to another. It is the pri-
mary mechanism for heat transfer between solids.
Conduction heat transfer is governed by Fourier’s law.
The thermal resistance equations, 1 and 1a, men-
tioned previously can be derived using Fourier’s law
stating that the rate of heat flow (P) through a material
is proportional to the cross sectional area (A) of the
material normal to the heat flow, the temperature gra-
dient (T) along the thickness (x) of the material, and
the thermal conductivity (K), a constant and a basic
property of the material. The value of K is in units
of W/
°C-cm mathematically:
expressed in units of W/cm2,
and hence:
Now look at the definition of heat capacity or the time
rate of heat flow.
Tj
ID
Ta
Tc
sa
θ
a. without heat sink
b. with heat sink
Heat sink
Insulator
...........................................
Tj
Tc
Ts
Ta
jc
θ
cs
θ
ja
θ
sa
θ
ca
θ
Tj = Junction Temperature
Tc = Case Temperature
Ts = Sink Temperature
Ta = Air Temperature
Without heat sink
With heat sink
θja = θjc + θca
θja = θjc + θcs + θja
Tc
Pmax
(500 mW)
TC0
TC1
TcM
100°C
125°C
200 mW
DF = Pmax
Tcm– Tc0
= 1
θ
jc
= 12 mW/ C
°
P
2
()
PKA
dT dx
()
kA x
()
T2
T1
()
=
=
3
()
T
θ P where
θ xKA
=
PdQ dt
=
APPENDIX
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