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| 型号： | A8510GECTR-T |
| 厂商： | Allegro Microsystems Inc |
| 文件页数： | 25/33页 |
| 文件大小： | 0K |
| 描述： | IC LED DRVR BCKLGHT/WHT 26QFN-EC |
| 标准包装： | 1 |
| 拓扑： | PWM，升压（升压） |
| 输出数： | 8 |
| 内部驱动器： | 是 |
| 类型 - 主要： | 背光 |
| 类型 - 次要： | 白色 LED |
| 频率： | 600kHz ~ 2.25MHz |
| 电源电压： | 5 V ~ 40 V |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 26-WFQFN 裸露焊盘 |
| 供应商设备封装： | 26-QFN/MLP-EP（4x4） |
| 包装： | 标准包装 |
| 工作温度： | -40°C ~ 105°C |
| 其它名称： | 620-1385-6 |
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A8510
Wide Input Voltage Range, High Efficiency
Fault Tolerant LED Driver
Step 4a Determining the duty cycle, calculated as follows:
Then:
D (max) = 1 –
V IN (min)
V OUT(OVP) + V d
(11)
L =
V IN (min)
Δ I L f SW
D (max)
(16)
= 1 –
10 V
41.7 V + 0.4 V
= 76.3%
=
10 V
0.444 A 800 kHz
0.76 = 21.4 μ H
The voltage drop of the diode can be approximated to be about
0.4 V.
Step 4b Determining the maximum and minimum input current
to the system. The minimum input current will dictate the induc-
tor value. The maximum current rating will dictate the current
rating of the inductor. First, the maximum input current, given:
I OUT = # CHANNELS I LED (12)
Step 4d Double-check to make sure the ? current ripple is less
than I IN (min):
I IN (min) > 1 / 2 Δ I L (17)
1.059 A > 0.222 A
A good inductor value to use would be 22 μ H, L used .
Step 4e This step is used to verify that there is sufficient slope
compensation for the inductor chosen. The slope compensation
value is determined by the following formula:
Slope Compensation = = 1.8 A / μ s
then:
= 8
0.040 A = 0.320 A
4.5 f SW
2 10 6
(18)
I IN (max) =
= = 1.483 A
V IN (min) D (max)
= 0.434 A
=
I IN (min) =
Δ I Lused
1 10 – 6
Slope (min) =
(1 – D (max))
V OUT(OVP) I OUT
V IN (min)
41.7 V 0.320 A
10 V 0.9
where η is efficiency.
Next, calculate minimum input current, as follows:
V OUT(OVP) I OUT
V IN (max)
(13)
(14)
Next insert the inductor value used in the design:
Δ I Lused =
L used f SW
10 V 0.763
22 μ H 800 kHz
Calculate the minimum required slope:
Required
1
f SW
(19)
(20)
= = 1.059 A
41.7 V 0.320 A
14 V 0.9
=
0.434 A
1
800 kHz
1 10 – 6
= 1.46 A/ μ s
(1 – 0.763)
A good approximation of efficiency, η , can be taken from the
efficiency curves located in the diode datasheet. A value of 90%
is a good starting approximation.
Step 4c Determining the inductor value. To ensure that the
inductor operates in continuous conduction mode, the value of
the inductor must be set such that the ? inductor ripple current is
not greater than the average minimum input current. A first past
assumes I ripple to be 30% of the maximum inductor current:
If the minimum required slope is larger than the calculated slope
compensation, the inductor value must be increased.
Note: that the slope compensation value is in A/ μ s, and 1 × 10 –6 is
a constant multiplier.
Step 4f Determining the inductor current rating. The inductor
current rating must be greater than the I IN (max) value plus the
ripple current Δ I L , or about 1.7 A, calculated as follows:
Δ I L = I IN (max) × 0.3
= 1.48 A × 0.3 = 0.444 A
(15)
I L (min) = I IN (max) + 1 / 2 Δ I Lused
= 1.483 A + 0.217 A = 1.70 A
Allegro MicroSystems, LLC
115 Northeast Cutoff
(21)
25
Worcester, Massachusetts 01615-0036 U.S.A.
1.508.853.5000; www.allegromicro.com
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