参数资料
| 型号： | IP1203TR |
| 厂商： | International Rectifier |
| 文件页数： | 16/23页 |
| 文件大小： | 0K |
| 描述： | IC REG BUCK SYNC ADJ 15A 24LGA |
| 产品变化通告： | (EP) Parts Discontinuation 25/May/2012 |
| 标准包装： | 1,000 |
| 系列： | iPOWIR™ |
| 类型： | 降压（降压） |
| 输出类型： | 可调式 |
| 输出数： | 1 |
| 输出电压： | 0.8 V ~ 8 V |
| 输入电压： | 5.5 V ~ 13.2 V |
| 频率 - 开关： | 200kHz ~ 400kHz |
| 电流 - 输出： | 15A |
| 同步整流器： | 是 |
| 工作温度： | -10°C ~ 125°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 24-LGA |
| 包装： | 带卷 (TR) |
| 供应商设备封装： | LGA（9x9） |
| 配用： | IRDCIP1203-A-ND - IP1203 REFERENCE DESIGN KIT |
iP1203
1
2 π × R 21 × C 8
f p 3 =
1
2 π × R 20 × C 7
f z 1 =
2 π × R 20 × C 9
put capacitor C o and determine the value of R 21 from
equation (19). Make sure R 21 <
V
R 5 = R 2 x
(24)
V -V
Thefrequenciesofthethreepolesandthetwozeros
of the Type III compensation scheme are represented
by the following equations:
f p1 = 0 (18)
(19)
f p 2 =
(20)
1
(21)
7. Place the second pole f p2 at or near f esr of the out-
R 2
10
8. Use equation (24) to calculate R 5 .
ref
o ref
More than one iteration may be required to calculate
the values of the compensation components if cross-
over frequencies higher than the range specified in
step 1 are required (for higher bandwidths and faster
transient response performance). To ensure stability
a phase margin greater than 45° should be achieved.
Refer to AN-1043 for more detailed compensation
techniques using Transconductance Amplifiers.
f z 2 =
1
2 π × R 2 × C 8
(22)
The crossover frequency f 0 for Type III compensa-
tion is represented by equation (23):
f 0 =
1
V ramp
× V IN × R 20 × C 8 ×
1
2 π × L 0 × C 0
(23)
Select C7 such that C 7 <
Follow the steps below to determine the feedback
loop compensation component values:
1. Select a zero db crossover frequency f 0 in the range
of 10% to 20% of the switching frequency f sw.
2. Select R 20 ~ 10k ?
3. Place the first zero f z1 at 75% of the resonant fre-
quency f LC of the output filter.
Determine C 9 from equation (21).
4. Place a third pole f P3 at or near the switching fre-
quency f SW .
C 9
10
5. Calculate C 8 from equation (23).
6. Place the second zero at 125% of the resonant
frequency f LC of the output filter. Calculate R 2 using
equation (22).
16
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