参数资料
型号: IRU3046CFTR
厂商: International Rectifier
文件页数: 10/20页
文件大小: 0K
描述: IC REG CTRLR BUCK PWM VM 24TSSOP
标准包装: 1
PWM 型: 电压模式
输出数: 2
频率 - 最大: 450kHz
占空比: 90%
电源电压: 5 V ~ 12 V
降压:
升压:
回扫:
反相:
倍增器:
除法器:
Cuk:
隔离:
工作温度: 0°C ~ 70°C
封装/外壳: 24-TSSOP(0.173",4.40mm 宽)
包装: 剪切带 (CT)
产品目录页面: 1384 (CN2011-ZH PDF)
其它名称: *IRU3046CFTR
IRU3046CFCT
IRU3046
The pole sets to one half of switching frequency which
results in the capacitor C POLE:
As known, transconductance amplifier has high imped-
ance (current source) output, therefore, consider should
1
C POLE =
p 3 R 4 3 f S -
f S
For F P <<
2
1
C 9
?
1
p 3 R 4 3 f S
be taken when loading the E/A output. It may exceed its
source/sink output current capability, so that the ampli-
fier will not be able to swing its output voltage over the
necessary range.
For a general solution for unconditionally stability for any
type of output capacitors, in a wide range of ESR values
we should implement local feedback with a compensa-
The compensation network has three poles and two ze-
ros and they are expressed as follows:
F P1 = 0
tion network. The typically used compensation network
for voltage-mode controller is shown in Figure 7.
F P2 =
1
2 p3 R 8 3 C 10
( C C 3 +C C )
Z IN
C 10
V OUT
R 7
C 12
C 11
F P3 =
2 p3 R 7 3
1
12 11
12 11
?
1
2 p3 R 7 3 C 12
R 8
R 6
Z f
F Z1 =
1
2 p3 R 7 3 C 11
R 5
Fb1
E/A1
Comp1
Ve
F Z2 =
1
2 p3 C 10 3 (R 6 + R 8 )
?
1
2 p3 C 10 3 R 6
Gain(dB)
V REF
Cross Over Frequency:
V IN
F O1 = R 7 3 C 10 3
V OSC
3
1
2 p3 Lo 3 Co
---(16)
H(s) dB
Where:
V IN = Maximum Input Voltage
V OSC = Oscillator Ramp Voltage
F Z 1
F Z 2
F P 2
F P 3
Frequency
Lo = Output Inductor
Co = Total Output Capacitors
g m Z IN
V OUT
Figure 7 - Compensation network with local
feedback and its asymptotic gain plot.
In such configuration, the transfer function is given by:
V e 1- g m Z f
=
1+
The error amplifier gain is independent of the transcon-
ductance under the following condition:
The stability requirement will be satisfied by placing the
poles and zeros of the compensation network according
to following design rules. The consideration has been
taken to satisfy condition (15) regarding transconduc-
tance error amplifier.
1) Select the crossover frequency:
Fo < F ESR and Fo [ (1/10 ~ 1/6) 3 f S
g m Z f >> 1 and g m Z IN >>1 ---(15)
By replacing Z IN and Z f according to figure 7, the trans-
2) Select R 7 , so that R 7 >>
2
g m
former function can be expressed as:
3) Place first zero before LC’s resonant frequency pole.
[ ( )]
3 (1+sR 8 C 10 )
1+sR 7
2 p 3 F Z1 3 R 7
H(s)=
1
3
sR 6 (C 12 +C 11 )
(1+sR 7 C 11 ) 3 [1+sC 10 (R 6 +R 8 )]
C 12 C 11
C 12 +C 11
F Z1 ? 75% F LC
1
C 11 =
10
www.irf.com
Rev. 1.9
09/27/02
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