参数资料
型号: LT1913IDD#TRPBF
厂商: Linear Technology
文件页数: 14/24页
文件大小: 0K
描述: IC REG BUCK ADJ 3.5A 10DFN
标准包装: 2,500
类型: 降压(降压)
输出类型: 可调式
输出数: 1
输出电压: 0.79 V ~ 25 V
输入电压: 3.6 V ~ 25 V
PWM 型: 电流模式
频率 - 开关: 200kHz ~ 2.4MHz
电流 - 输出: 3.5A
同步整流器:
工作温度: -40°C ~ 125°C
安装类型: 表面贴装
封装/外壳: 10-WFDFN 裸露焊盘
包装: 带卷 (TR)
供应商设备封装: 10-DFN(3x3)
LT1913
APPLICATIONS INFORMATION
V C pin, as shown in Figure 2. Generally a capacitor (C C )
and a resistor (R C ) in series to ground are used. In addi-
tion, there may be lower value capacitor in parallel. This
capacitor (C F ) is not part of the loop compensation but
is used to ?lter noise at the switching frequency, and is
required only if a phase-lead capacitor is used or if the
output capacitor has high ESR.
Loop compensation determines the stability and transient
BOOST and BIAS Pin Considerations
Capacitor C3 and the internal boost Schottky diode (see
the Block Diagram) are used to generate a boost volt-
age that is higher than the input voltage. In most cases
a 0.47μF capacitor will work well. Figure 2 shows three
ways to arrange the boost circuit. The BOOST pin must be
LT1913
performance. Designing the compensation network is a bit
complicated and the best values depend on the application
and in particular the type of output capacitor. A practical
CURRENT MODE
POWER STAGE
g m = 5.3mho
ERROR
AMPLIFIER
SW
R1
C PL
OUTPUT
approach is to start with one of the circuits in this data
sheet that is similar to your application and tune the com-
pensation network to optimize the performance. Stability
3M
g m =
525μmho
FB
0.8V
ESR
+
C1
should then be checked across all operating conditions,
C1
including load current, input voltage and temperature. The
LT1375 data sheet contains a more thorough discussion of
loop compensation and describes how to test the stabil-
ity using a transient load. Figure 2 shows an equivalent
C F
V C
R C
GND
R2
POLYMER
OR
TANTALUM
CERAMIC
circuit for the LT1913 control loop. The error ampli?er is a
transconductance ampli?er with ?nite output impedance.
The power section, consisting of the modulator, power
switch and inductor, is modeled as a transconductance
ampli?er generating an output current proportional to
the voltage at the V C pin. Note that the output capacitor
integrates this current, and that the capacitor on the V C pin
(C C ) integrates the error ampli?er output current, resulting
in two poles in the loop. In most cases a zero is required
and comes from either the output capacitor ESR or from
a resistor R C in series with C C . This simple model works
well as long as the value of the inductor is not too high
and the loop crossover frequency is much lower than the
switching frequency. A phase lead capacitor (C PL ) across
C C
Figure 2. Model for Loop Response
V OUT
100mV/DIV
I L
1A/DIV
1913 F02
the feedback divider may improve the transient response.
Figure 3 shows the transient response when the load cur-
10μs/DIV
1913 F03
rent is stepped from 1A to 3A and back to 1A.
Figure 3. Transient Load Response of the LT1913 Front Page
Application as the Load Current is Stepped from 1A to 3A.
V OUT = 5V
1913f
14
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