参数资料
型号: MAX753ESE+T
厂商: Maxim Integrated
文件页数: 8/16页
文件大小: 0K
描述: IC CNTRLR CONTRAST 16-SOIC
产品培训模块: Lead (SnPb) Finish for COTS
Obsolescence Mitigation Program
标准包装: 2,500
显示器类型: CCFL - 冷色阴极荧光灯
电流 - 电源: 500µA
电源电压: 4 V ~ 30 V
工作温度: -40°C ~ 85°C
安装类型: 表面贴装
封装/外壳: 16-SOIC(0.154",3.90mm 宽)
供应商设备封装: 16-SOIC
包装: 带卷 (TR)
CCFL Backlight and
LCD Contrast Controllers
BATTERY
INPUT
2
3
C1
0.22 μ F
+5V INPUT
1
15
14
L2
33 μ H
C2
10 μ F
D3
1N5819
POSITIVE
LCD-BIAS
OUTPUT
LADJ
LON
V DD
BATT
LX
CONTROL ON/OFF
PRESET
ON-TIME
LOGIC
OFF-TIME
LOGIC
PULSE-SKIP
COMPARATOR
LDRV 13
LFB 16
Q3
R3
C6
10 μ F
35V
6-BIT COUNTER
CLK
V DAC
R4
MAX754
PGND
12
6-BIT DAC
GND
6
FULL-SCALE OUTPUT = 1.250V
HALF-SCALE OUTPUT = 0.938V
ZERO-SCALE OUTPUT = 0.635V
Figure 6. MAX754 Positive LCD-Bias Generator
Table 1. CCFL Circuit Component Descriptions
ITEM
C5
R18
R8
D7A, D7B
CCFL
DESCRIPTION
Integrating Capacitor. 1 / (C5 x R18) sets the dominant pole for the feedback loop, which regulates the lamp
current. Set the dominant pole at least two decades below the Royer frequency to eliminate the AC compo-
nent of the voltage on R8. For example, if your Royer is oscillating at 50kHz = 314159rad/s, you should set
1 / (C5 x R18) ≤ 3142rad/s.
Integrating Resistor. The output source-current capability of the CC pin (50μA) limits how small R18 can be.
Do not make R18 smaller than 70k ? , otherwise CC will not be able to servo CFB to the DAC voltage (i.e., the
integrator will not be able to integrate) and the loop will not be able to regulate.
R8 converts the half-wave rectified lamp current into a voltage. The average voltage on R8 is not equal to the
root mean square voltage on R8. The accuracy of R8 is important since it, along with the MAX754 reference,
sets the full-scale lamp current. Use a ±1%-accurate resistor.
D7A and D7B half-wave rectify the CCFL lamp current. Half-wave rectification of the lamp current and then
averaging is a simple way to perform AC-to-DC conversion. D7A and D7B’s forward voltage drop and speed
are unimportant; they do not need to pass currents larger than about 10mA, and their reverse breakdown
voltage can be as low as 10V.
The circuit of Figure 1, with the components shown in the bill of materials (Table 4), will drive a 500V RMS oper-
ating cold-cathode fluorescent lamp at 6W of power with a +12V input voltage. The lower the input voltage,
the less power the circuit can deliver.
8
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