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| 型号： | TPS54160DGQR |
| 厂商： | TEXAS INSTRUMENTS INC |
| 元件分类： | 稳压器 |
| 英文描述： | 2.7 A SWITCHING REGULATOR, 2500 kHz SWITCHING FREQ-MAX, PDSO10 |
| 封装： | GREEN, PLASTIC, MSOP-10 |
| 文件页数： | 24/50页 |
| 文件大小： | 1375K |
| 代理商： | TPS54160DGQR |
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SLVS795C – OCTOBER 2008 – REVISED OCTOBER 2010
www.ti.com
to see the change in load current and output voltage and adjust the duty cycle to react to the change. The output
capacitor must be sized to supply the extra current to the load until the control loop responds to the load change.
The output capacitance must be large enough to supply the difference in current for twoclock cycles while only
allowing a tolerable amount of droop in the output voltage. Equation 32 shows the minimum output capacitance
necessary to accomplish this.
Where
ΔIOUT is the change in output current, sw is the regulators switching frequency and ΔVout is the
allowable change in the output voltage. For this example, the transient load response is specified as a 4%
change in VOUT for a load step from 0 A (no load) to 1.5 A (full load). For this example, ΔIOUT = 1.5-0 = 1.5 A and
ΔVOUT = 0.04 × 3.3 = 0.132 V. Using these numbers gives a minimum capacitance of 18.9 mF. This value does
not take the ESR of the output capacitor into account in the output voltage change. For ceramic capacitors, the
ESR is usually small enough to ignore in this calculation. Aluminum electrolytic and tantalum capacitors have
higher ESR that should be taken into account.
The catch diode of the regulator cannot sink current so any stored energy in the inductor produces an output
voltage overshoot when the load current rapidly decreases, see Figure 52. The output capacitor must also be
sized to absorb energy stored in the inductor when transitioning from a high load current to a lower load current.
The excess energy that gets stored in the output capacitor increases the voltage on the capacitor. The capacitor
must be sized to maintain the desired output voltage during these transient periods. Equation 33 is used to
calculate the minimum capacitance to keep the output voltage overshoot to a desired value. Where L is the value
of the inductor, IOH is the output current under heavy load, IOL is the output under light load, Vf is the final peak
output voltage, and Vi is the initial capacitor voltage. For this example, the worst case load step will be from 1.5
A to 0 A. The output voltage increases during this load transition and the stated maximum in our specification is
4% of the output voltage. This will make Vf = 1.04 × 3.3 = 3.432. Vi is the initial capacitor voltage which is the
nominal output voltage of 3.3 V. Using these numbers in Equation 33 yields a minimum capacitance of 25.3 mF.
Equation 34 calculates the minimum output capacitance needed to meet the output voltage ripple specification.
Where fSW is the switching frequency, VOUT(ripple) is the maximum allowable output voltage ripple, and Iripple is the
inductor ripple current. Equation 34 yields 0.7 mF.
Equation 35 calculates the maximum ESR an output capacitor can have to meet the output voltage ripple
specification. Equation 35 indicates the ESR should be less than 147 m
.
The most stringent criteria for the output capacitor is 25.3 mF of capacitance to keep the output voltage in
regulation during an unload transient.
Additional capacitance de-ratings for aging, temperature and dc bias should be factored in which increases this
minimum value. For this example, a 47 mF 6.3V X7R ceramic capacitor with 5 m of ESR is used.
Capacitors generally have limits to the amount of ripple current they can handle without failing or producing
excess heat. An output capacitor that can support the inductor ripple current must be specified. Some capacitor
data sheets specify the Root Mean Square (RMS) value of the maximum ripple current. Equation 36 can be used
to calculate the RMS ripple current the output capacitor needs to support. For this application, Equation 36 yields
64.8 mA.
(32)
(33)
(34)
30
Copyright 2008–2010, Texas Instruments Incorporated
Product Folder Link(s): TPS54160
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