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| 型号： | A8515GLPTR-T |
| 厂商： | Allegro Microsystems Inc |
| 文件页数： | 26/34页 |
| 文件大小： | 0K |
| 描述： | IC LED DVR WHT/RGB BKLGT 16TSSOP |
| 标准包装： | 8,000 |
| 拓扑： | PWM，升压（升压） |
| 输出数： | 2 |
| 内部驱动器： | 是 |
| 类型 - 主要： | 背光 |
| 类型 - 次要： | 白色 LED |
| 频率： | 600kHz ~ 2.5MHz |
| 电源电压： | 5 V ~ 40 V |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 16-TSSOP（0.173"，4.40mm）裸露焊盘 |
| 供应商设备封装： | 16-TSSOP-EP |
| 包装： | 带卷 (TR) |
| 工作温度： | -40°C ~ 105°C |
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A8515
Wide Input Voltage Range, High Efficiency
Fault Tolerant LED Driver
Step 4a Determining the duty cycle, calculated as follows:
Step 4d Double-check to make sure the ? current ripple is less
D (max) = 1 –
V IN (min)
V OUT(OVP) + V d
(12)
than I IN (min):
I IN (min) > 1 / 2 Δ I L
0.75 A > 0.21 A
(18)
1 –
= = 74.9%
Slope Compensation = = 3.6 A / μ s
2 10 6
10 V
39.5 + 0.4
Step 4b Determining the maximum and minimum input current
to the system. The minimum input current will dictate the induc-
tor value. The maximum current rating will dictate the current
rating of the inductor. First, the maximum input current, given:
A good inductor value to use would be 10 μ H.
Step 4e This step is used to verify that there is sufficient slope
compensation for the inductor chosen. The slope compensation
value is determined by the following formula:
3.6 f SW
(19)
I OUT = # CHANNELS
I LED
(13)
Next insert the inductor value used in the design:
I IN (max) =
= 1.053 A
=
V IN (min) D (max)
=
= 2 0.120 A =0.240A
then:
V OUT(OVP) I OUT
V IN (min)
39.5 V 240 mA
10 V 0.9
where η is efficiency.
(14)
Δ I Lused =
L used f SW
10 (V) 0.75
10 ( μ H) 2.0 (MHz)
Calculate the minimum required slope:
= 0.37 A
(20)
I IN (min) =
= = 0.752 A
(1 – D (max))
(1 – 0.75)
Next, calculate minimum input current, as follows:
V OUT(OVP) I OUT
V IN (max)
39.5 V 240 mA
14 V 0.9
(15)
Required Slope (min) =
=
Δ I Lused 1 10 – 6
1
f SW
1
2.0 (MHz)
0.37 (A) 1 10 – 6
= 2.97 A/ μ s
(21)
A good approximation of efficiency, η , can be taken from the
efficiency curves located in the diode datasheet. A value of 90%
is a good starting approximation.
Step 4c Determining the inductor value. To ensure that the
inductor operates in continuous conduction mode, the value of
the inductor must be set such that the ? inductor ripple current is
not greater than the average minimum input current. A first past
If the minimum required slope is greater than the calculated slope
compensation, the inductor value must be increased.
Note: The slope compensation value is in A/ μ s, and 1 × 10 –6 is a
constant multiplier.
Step 4f Determining the inductor current rating. The inductor
assumes I ripple to be 40% of the maximum inductor current:
Δ I L = I IN (max) × 0.4
(16)
current rating must be greater than the I IN (max) value plus the
ripple current Δ I L , calculated as follows:
then:
= 1.05 A × 0.4 = 0.42 A
I L (max) = I IN (max) + 1 / 2 Δ I Lused
= 1.05 A + 0.37 A / 2 = 1.24 A
(22)
V IN (min)
L =
=
Δ I L f SW
D (max)
10 V
0.42 A 2 MHz
0.749 = 8.9 μ H
(17)
Step 5 Determining the resistor value for a particular switching
frequency. Use the R FSET values shown in figure 7. For example,
a 10 k Ω resistor will result in a 2 MHz switching frequency.
Step 6 Choosing the proper switching diode. The switching
diode must be chosen for three characteristics when it is used in
Allegro MicroSystems, LLC
115 Northeast Cutoff
Worcester, Massachusetts 01615-0036 U.S.A.
1.508.853.5000; www.allegromicro.com
26
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