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| 型号： | A8515GLPTR-T |
| 厂商： | Allegro Microsystems Inc |
| 文件页数： | 30/34页 |
| 文件大小： | 0K |
| 描述： | IC LED DVR WHT/RGB BKLGT 16TSSOP |
| 标准包装： | 8,000 |
| 拓扑： | PWM，升压（升压） |
| 输出数： | 2 |
| 内部驱动器： | 是 |
| 类型 - 主要： | 背光 |
| 类型 - 次要： | 白色 LED |
| 频率： | 600kHz ~ 2.5MHz |
| 电源电压： | 5 V ~ 40 V |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 16-TSSOP（0.173"，4.40mm）裸露焊盘 |
| 供应商设备封装： | 16-TSSOP-EP |
| 包装： | 带卷 (TR) |
| 工作温度： | -40°C ~ 105°C |
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A8515
Wide Input Voltage Range, High Efficiency
Fault Tolerant LED Driver
tions, due to stringent EMI requirements, the system must operate
then:
V OUT(OVP) + V d
V IN (min)
in continuous conduction mode throughout the whole input volt-
age range.
Step 4a Determining the duty cycle, calculated as follows:
D (max) = (35)
V IN (min) + V OUT(OVP) + V d
L =
=
Δ I L f SW
D (max)
5 (V)
0.254 (A) 2 (MHz)
0.765 = 7.53 μ H
(40)
=
15.9 (V) + 0.4 (V)
5 (V) + 15.9 (V) + 0.4 (V)
= 76.5%
Step 4d Double-check to make sure the ? current ripple is less
than I IN (min):
Step 4b Determining the maximum and minimum input current
to the system. The minimum input current will dictate the induc-
tor value. The maximum current rating will dictate the current
rating of the inductor. First, the maximum input current, given:
I IN (min) > 1 / 2 Δ I L
0.265 A > 0.127 A
A good inductor value to use would be 10 μ H.
(41)
I OUT = # CHANNELS
I LED
(36)
Step 4e Next insert the inductor value used in the design to
then:
= 2
120 (mA) = 0.240 A
determine the actual inductor ripple current:
I IN (max) =
=
V OUT(OVP) I OUT
V IN (min)
15.9 (V) 0.24 (A)
5 (V) 0.90
= 0.848 A
(37)
Δ I Lused =
=
V IN (min) D (max)
L used f SW
5 (V) 0.765
10 ( μ H) 2 (MHz)
= 0.191 A
(42)
I IN (min) =
where η is efficiency.
Next, calculate minimum input current, as follows:
V OUT(OVP) I OUT
V IN (max)
(38)
Step 4f Determining the inductor current rating. The inductor
current rating must be greater than the I IN (max) value plus half of
the ripple current Δ I L , calculated as follows:
L (min) = I IN (max) + 1 / 2 Δ I Lused (43)
=
15.9 (V)
16 (V)
0.24 (A)
0.90
= 0.265 A
= 0.848 (A) + 0.096 (A) = 0.944 A
Step 5 Determining the resistor value for a particular switching
Step 4c Determining the inductor value. To ensure that the
inductor operates in continuous conduction mode, the value of
the inductor must be set such that the ? inductor ripple current
is not greater than the average minimum input current. As a first
pass assume I ripple to be 30% of the maximum inductor current:
frequency. Use the R FSET values shown in figure 6. For example,
a 10 k Ω resistor will result in an 2 MHz switching frequency.
Step 6 Choosing the proper switching diode. The switching
diode must be chosen for three characteristics when it is used in
Δ I L = I IN (max) × I ripple
= 0.848 × 0.30 = 0.254 A
(39)
LED lighting circuitry. The most obvious two are: current rating
of the diode and reverse voltage rating.
30
Allegro MicroSystems, LLC
115 Northeast Cutoff
Worcester, Massachusetts 01615-0036 U.S.A.
1.508.853.5000; www.allegromicro.com
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