参数资料
| 型号： | NCP5380AMNR2G |
| 厂商： | ON Semiconductor |
| 文件页数： | 21/28页 |
| 文件大小： | 0K |
| 描述： | IC CTLR SYNC BUCK SGL 32QFN |
| 标准包装： | 5,000 |
| 应用： | 控制器，Intel VR11 |
| 输入电压： | 5V |
| 输出数： | 1 |
| 输出电压： | 0.5 V ~ 1.6 V |
| 工作温度： | -40°C ~ 100°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 32-VFQFN 裸露焊盘 |
| 供应商设备封装： | 32-QFN（5x5） |
| 包装： | 带卷 (TR) |
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NCP5380, NCP5380A
C CS + + 2.2 nF
Where R SENSE is the DCR of the output inductors.
Either RCS or RPH can be chosen for added flexibility.
Due to the current drive ability of the CSCOMP pin, the RCS
resistance should be greater than 100 k W . For example,
initially select RCS to be equal to 200 k W , and then use
Equation 10 to solve for CCS:
560 nH
1.3 m W 200 k W
If C CS is not a standard capacitance, R CS can be tuned. In this
case, the required C CS is a standard value and no tuning is
required. For best accuracy, C CS should be a 5% NPO
capacitor.
R TH (50 ° C)/R TH (25 ° C)) and B (B is
R TH (90 ° C)/R TH (25 ° C)). Note that the relative
value of the NTC is always 1 at 25 ° C.
3. Find the relative value of R CS required for each of
the two temperatures. The relative value of R CS is
based on the percentage of change needed, which
is initially assumed to be 0.39%/ ° C in this
example. The relative values are called r 1 (r 1 is
1/(1+ TC x ( T 1 ? 25))) and r 2 (r 2 is 1/(1 + TC x
( T 2 ? 25))), where TC is 0.0039, T 1 is 50 ° C, and
T 2 is 90 ° C.
4. Compute the relative values for r CS1 , r CS2 , and r TH
by using the following equations:
R PH w 200 k W + 51.0 k W
1 * r * r * r
Next, solve for RPH by rearranging Equation 9 as follows:
1.3 m W
5.1 m W
The standard 1% resistor for R PH is 51.1 k W .
r cs +
A * B
A
r 1 r 2 * A 1 * B r 2 ) B 1 * A
1 * B r 1 * B 1 * A r 2 * A * B
r CS1 + 1 A
(1 * A)
CS2 1 CS2
r 1
R TH
as possible to To V OUT
Sense
NCP5380 R C51 R C52
well away from the
1 * r * r
R CS1 + R CS
r CS1
?
C C51
Inductor DCR Temperature Correction
If the DCR of the inductor is used as a sense element and
copper wire is the source of the DCR, the temperature
changes associated with the inductor ’s winding must be
compensated for. Fortunately, copper has a well ? known
temperature coefficient (TC) of 0.39%/ ° C.
If RCS is designed to have an opposite but equal
percentage of change in resistance, it cancels the
temperature variation of the inductor ’s DCR. Due to the
nonlinear nature of NTC thermistors, series resistors RCS1
and RCS2 (see Figure 24) are needed to linearize the NTC
and produce the desired temperature coefficient tracking.
Place as close
To Switch Node
nearest inductor
R TH
Keep this path as
short as possible and
16
Switch Node Lines
15
+ 14
Figure 24. Temperature ? Compensation Circuit
Values
The following procedure and expressions yield values for
R CS1 , R CS2 , and R TH (the thermistor value at 25 ° C) for a
given R CS value.
1. Select an NTC to be used based on its type and
value. Because the value needed is not yet
determined, start with a thermistor with a value
close to R CS and an NTC with an initial tolerance
of better than 5%.
2. Find the relative resistance value of the NTC at
two temperatures. The appropriate temperatures
will depend on the type of NTC, but 50 ° C and
90 ° C have been shown to work well for most types
of NTCs. The resistance values are called A (A is
(1)
r TH + 1 1
CS2 CS2
5. Calculate R TH = r TH x R CS , and then select a
thermistor of the closest value available. In
addition, compute a scaling factor k based on the
ratio of the actual thermistor value used relative to
the computed one:
R TH(ACTUAL)
k + (eq. 11)
R TH(CALCULATED)
6. Calculate values for R CS1 and R CS2 by using the
following equations:
k (eq. 12)
R CS2 + R CS (1 * k ) ) k r CS2
For example, if a thermistor value of 100 k W is selected
in Step 1, an available 0603 ? size thermistor with a value
close to R CS is the Vishay NTHS0603N04 NTC thermistor,
which has resistance values of A = 0.3359 and B = 0.0771.
Using the equations in Step 4, r CS1 is 0.359, r CS2 is 0.729,
and r TH is 1.094. Solving for r TH yields 219 k W , so a
thermistor of 220 k W would be a reasonable selection,
making k equal to 1.005. Finally, R CS1 and R CS2 are found
to be 72.2 k W and 146 k W . Choosing the closest 1% resistor
values yields a choice of 71.5 k W and 147 k W .
C out SELECTION
The required output decoupling for processors and
platforms is typically recommended by Intel. For systems
containing both bulk and ceramic capacitors, however, the
following guidelines can be a helpful supplement.
Select the number of ceramics and determine the total
ceramic capacitance (C Z ). This is based on the number and
type of capacitors used. Keep in mind that the best location
to place ceramic capacitors is inside the socket; however, the
http://onsemi.com
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相关代理商/技术参数 |
参数描述 |
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| NCP5380MNR2G | 功能描述:DC/DC 开关控制器 IMVP6.5 BUCK CTRL RoHS:否 制造商:Texas Instruments 输入电压:6 V to 100 V 开关频率: 输出电压:1.215 V to 80 V 输出电流:3.5 A 输出端数量:1 最大工作温度:+ 125 C 安装风格: 封装 / 箱体:CPAK |
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| NCP5381AMNR2G | 功能描述:DC/DC 开关控制器 2/3/4 PHASE CNTRLR RoHS:否 制造商:Texas Instruments 输入电压:6 V to 100 V 开关频率: 输出电压:1.215 V to 80 V 输出电流:3.5 A 输出端数量:1 最大工作温度:+ 125 C 安装风格: 封装 / 箱体:CPAK |
| NCP5381MNR2G | 功能描述:DC/DC 开关控制器 ANA 2/3/4 PHSE BUCK CNTLR RoHS:否 制造商:Texas Instruments 输入电压:6 V to 100 V 开关频率: 输出电压:1.215 V to 80 V 输出电流:3.5 A 输出端数量:1 最大工作温度:+ 125 C 安装风格: 封装 / 箱体:CPAK |
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