参数资料
| 型号： | CS5165AGDW16 |
| 厂商： | ON Semiconductor |
| 文件页数： | 15/18页 |
| 文件大小： | 0K |
| 描述： | IC CTRLR BUCK SYNC 5BIT 16-SOIC |
| 产品变化通告： | Product Obsolescence 11/Feb/2009 Product Obsolescence 30/Dec/2003 |
| 标准包装： | 47 |
| 应用： | 控制器，Intel Pentium? II |
| 输入电压： | 8 V ~ 14 V |
| 输出数： | 2 |
| 输出电压： | 1.34 V ~ 2.09 V，2.14 V ~ 3.54 V |
| 工作温度： | 0°C ~ 70°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 16-SOIC（0.295"，7.50mm 宽） |
| 供应商设备封装： | 16-SOIC W |
| 包装： | 管件 |
CS5165A
Droop Resistor Tolerance
Tolerance due to sheet resistivity variation
Tolerance due to L/W error
Tolerance due to temperature variation
Total tolerance for droop resistor
16%
1.0%
12%
29%
For most PCBs the copper thickness, t, is 35 m m (1.37
mils) for one ounce copper. ρ = 717.86 mW ?mil
For a Pentium II load of 14.2 A the resistance needed to
create a 56 mV drop at full load is:
Response Droop + 56 mV + 56 mV + 3.9 m W
VDROOP(TYP) +
In order to determine the droop resistor value the nominal
voltage drop across it at full load has to be calculated. This
voltage drop has to be such that the output voltage full load
is above the minimum DC tolerance spec.
[VDAC(MIN) * VDC(MIN)]
1 ) RDROOP(TOLERANCE)
Example: for a 300 MHz PentiumII, the DC accuracy spec
is 2.74 < V CC(CORE) < 2.9 V, and the AC accuracy spec is
2.67 V < V CC(CORE) < 2.9 3V. The CS5165A DAC output
voltage is +2.812 V < V DAC < +2.868 V. In order not to
exceed the DC accuracy spec, the voltage drop developed
IOUT 14.2 A
The resistivity of the copper will drift with the
temperature according to the following guidelines:
D R + 12% @ TA + ) 50 ° C
D R + 34% @ TA + ) 100 ° C
Droop Resistor Width Calculations
The droop resistor must have the ability to handle the load
current and therefore requires a minimum width which is
calculated as follows (assume one ounce copper thickness):
VDROOP(TYP) +
W + LOAD
across the resistor must be calculated as follows:
[VDAC(MIN) * VDC PENTIUMII(MIN)]
1 ) RDROOP(TOLERANCE)
where:
I
0.05
+ 2.812 V * 2.74 V + 56 mV
W + 14.2 A + 284 mils + 0.7213 cm
1.3
With the CS5165A DAC accuracy being 1.0%, the internal
error amplifier’s reference voltage is trimmed so that the
output voltage will be 40 mV high at no load. With no load,
there is no DC drop across the resistor, producing an output
voltage tracking the error amplifier output voltage, including
W = minimum width (in mils) required for proper power
dissipation, and I LOAD Load Current Amps.
The Pentium ? II maximum load current is 14.2 A.
Therefore:
0.05
Droop Resistor Length Calculation
L +
+ 0.0039
the offset. When the full load current is delivered, a drop of
?56 mV is developed across the resistor. Therefore, the
regulator output is pre?positioned at 40 mV above the
nominal output voltage before a load turn?on. The total
RDROOP W
ò
284
717.86
t
1.37 + 2113 mil + 5.36 cm
voltage drop due to a load step is D V?40 mV and the
deviation from the nominal output voltage is 40 mV smaller
than it would be if there was no droop resistor. Similarly at full
load the regulator output is pre?positioned at 16 mV below
the nominal voltage before a load turn?off. The total voltage
increase due to a load turn?off is D V?16 mV and the
deviation from the nominal output voltage is 16 mV smaller
Output Inductor
The inductor should be selected based on its inductance,
current capability, and DC resistance. Increasing the
inductor value will decrease output voltage ripple, but
degrade transient response.
Inductor Ripple Current
than it would be if there was no droop resistor. This is because
the output capacitors are pre?charged to value that is either
Ripple Current +
[(VIN * VOUT)
(Switching Frequency
VOUT]
L VIN)
Ripple Current +
+ 5.1 A
L or R + ò
RAR + ò
40 mV above the nominal output voltage before a load
turn?on or, 16 mV below the nominal output voltage before
a load turn?off (see Figure 15).
Obviously, the larger the voltage drop across the droop
resistor ( the larger the resistance), the worse the DC and
load regulation, but the better the AC transient response.
Design Rules for Using a Droop Resistor
The basic equation for laying an embedded resistor is:
L
A (W t)
where:
A = W × t = cross?sectional area
ρ = the copper resistivity ( mW ? mil)
L = length (mils)
Example: V IN = +5.0 V, V OUT = +2.8 V, I LOAD = 14.2 A,
L = 1.2 m H, Freq = 200 kHz
[(5.0 V * 2.8 V) 2.8 V]
[200 kHz 1.2 m H 5.0 V]
Output Ripple Voltage
VRIPPLE + Inductor Ripple Current Output Capacitor ESR
Example:
V IN = +5.0 V, V OUT = +2.8 V, I LOAD = 14.2 A, L = 1.2 m H,
Switching Frequency = 200 kHz
Output Ripple Voltage = 5.1 A × Output Capacitor ESR
(from manufacturer ’s specs)
ESR of Output Capacitors to limit Output Voltage Spikes
W = width (mils)
t = thickness (mils)
http://onsemi.com
15
ESR +
D VOUT
D IOUT
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