参数资料
型号: SAK-XC2237M-104F40L
厂商: Infineon Technologies
文件页数: 92/107页
文件大小: 0K
描述: IC MCU 16BIT 320KB FLASH 64LQFP
标准包装: 1,900
系列: XC22xxM
核心处理器: C166SV2
芯体尺寸: 16/32-位
速度: 40MHz
连通性: CAN,EBI/EMI,I²C,LIN,SPI,SSC,UART/USART,USI
外围设备: I²S,POR,PWM,WDT
输入/输出数: 38
程序存储器容量: 832KB(832K x 8)
程序存储器类型: 闪存
RAM 容量: 50K x 8
电压 - 电源 (Vcc/Vdd): 3 V ~ 5.5 V
数据转换器: A/D 9x10b
振荡器型: 内部
工作温度: -40°C ~ 125°C
封装/外壳: 64-LQFP
包装: 带卷 (TR)
其它名称: SP000720382
XC2238M, XC2237M
XC2000 Family / Base Line
Electrical Parameters
Data Sheet
85
V2.1, 2011-07
The timing in the AC Characteristics refers to TCSs. Timing must be calculated using the
minimum TCS possible under the given circumstances.
The actual minimum value for TCS depends on the jitter of the PLL. Because the PLL is
constantly adjusting its output frequency to correspond to the input frequency (from
crystal or oscillator), the accumulated jitter is limited. This means that the relative
deviation for periods of more than one TCS is lower than for a single TCS (see formulas
and Figure 20).
This is especially important for bus cycles using waitstates and for the operation of
timers, serial interfaces, etc. For all slower operations and longer periods (e.g. pulse train
generation or measurement, lower baudrates, etc.) the deviation caused by the PLL jitter
is negligible.
The value of the accumulated PLL jitter depends on the number of consecutive VCO
output cycles within the respective timeframe. The VCO output clock is divided by the
output prescaler K2 to generate the system clock signal
f
SYS. The number of VCO cycles
is K2
× T, where T is the number of consecutive f
SYS cycles (TCS).
The maximum accumulated jitter (long-term jitter) D
Tmax is defined by:
D
Tmax [ns] = ±(220 / (K2 × fSYS) + 4.3)
This maximum value is applicable, if either the number of clock cycles T > (
f
SYS / 1.2) or
the prescaler value K2 > 17.
In all other cases for a timeframe of T
× TCS the accumulated jitter D
T is determined by:
D
T [ns] = DTmax × [(1 - 0.058 × K2) × (T - 1) / (0.83 × fSYS - 1) + 0.058 × K2]
f
SYS in [MHz] in all formulas.
Example, for a period of 3 TCSs @ 33 MHz and K2 = 4:
D
max = ±(220 / (4 × 33) + 4.3) = 5.97 ns (Not applicable directly in this case!)
D
3 = 5.97 × [(1 - 0.058 × 4) × (3 - 1) / (0.83 × 33 - 1) + 0.058 × 4]
= 5.97
× [0.768 × 2 / 26.39 + 0.232]
= 1.7 ns
Example, for a period of 3 TCSs @ 33 MHz and K2 = 2:
D
max = ±(220 / (2 × 33) + 4.3) = 7.63 ns (Not applicable directly in this case!)
D
3 = 7.63 × [(1 - 0.058 × 2) × (3 - 1) / (0.83 × 33 - 1) + 0.058 × 2]
= 7.63
× [0.884 × 2 / 26.39 + 0.116]
= 1.4 ns
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