参数资料
型号: ST72651AR6T1E/XXX
厂商: STMICROELECTRONICS
元件分类: 微控制器/微处理器
英文描述: 8-BIT, MROM, MICROCONTROLLER, PQFP64
封装: 10 X 10 MM, ROHS COMPLIANT, TQFP-64
文件页数: 152/161页
文件大小: 2656K
代理商: ST72651AR6T1E/XXX
ST72651AR6
90/161
Doc ID 7215 Rev 4
PWM/BRM GENERATOR (Cont’d)
BRM Generation
The BRM bits allow the addition of a pulse to wid-
en a standard PWM pulse for specific PWM cy-
cles. This has the effect of “fine-tuning” the PWM
Duty cycle (without modifying the base duty cycle),
thus, with the external filtering, providing additional
fine voltage steps.
The incremental pulses (with duration of TCPU) are
added to the beginning of the original PWM pulse.
The PWM intervals which are added to are speci-
fied in the 4-bit BRM register and are encoded as
shown in the following table. The BRM values
shown may be combined together to provide a
summation of the incremental pulse intervals
specified.
The pulse increment corresponds to the PWM res-
olution.
For example, if
– Data 18h is written to the PWM register
– Data 06h (00000110b) is written to the BRM reg-
ister
– with a 8MHz internal clock (125ns resolution)
Then 3.0
μs-long pulse will be output at 8 μs inter-
vals, except for cycles numbered 2,4,6,10,12,14,
where the pulse is broadened to 3.125
μs.
Note. If 00h is written to both PWM and BRM reg-
isters, the generator output will remain at “0”. Con-
versely, if both registers hold data 3Fh and 0Fh,
respectively, the output will remain at “1” for all in-
tervals 1 to 15, but it will return to zero at interval 0
for an amount of time corresponding to the PWM
resolution (TCPU).
An output can be set to a continuous “1” level by
clearing the PWM and BRM values and setting
POL = “1” (inverted polarity) in the PWM register.
This allows a PWM/BRM channel to be used as an
additional I/O pin if the DAC function is not re-
quired.
Table 30. Bit BRM Added Pulse Intervals
(Interval #0 not selected).
Figure 51. BRM pulse addition (PWM > 0)
BRM 4 - Bit Data
Incremental Pulse Intervals
0000
none
0001
i = 8
0010
i = 4,12
0100
i = 2,6,10,14
1000
i = 1,3,5,7,9,11,13,15
T
CPU x 64
T
CPU x 64
T
CPU x 64
T
CPU x 64 increment
m = 1
m = 0
m = 2
T
CPU x 64
m = 15
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