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| 型号： | TPS51727RHARG4 |
| 厂商： | TEXAS INSTRUMENTS INC |
| 元件分类： | 稳压器 |
| 英文描述： | DUAL SWITCHING CONTROLLER, 500 kHz SWITCHING FREQ-MAX, PQCC40 |
| 封装： | 6 X 6 MM, GREEN, PLASTIC, QFN-40 |
| 文件页数： | 21/42页 |
| 文件大小： | 0K |
| 代理商： | TPS51727RHARG4 |
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APPLICATION INFORMATION
Design Procedure
Choosing Initial Parameters
P P
40 A
I
0.4
8.0 A
2 phases
-
=
=
(6)
MAX
P P
V dT
L
I
-
=
(8)
(
)
(
)
f
OUT max
IN max
V
dT
V
=
(7)
SLUS806B – APRIL 2008 – REVISED JANUARY 2009 ..................................................................................................................................................... www.ti.com
The following section describes a very simple design procedure for the TPS51727, as a high-performance dual
phase power controller.
Step One
Determine the output requirements. For the purposes of this document, we use the following parameters for the
design procedure.
The processor requirements provide the following key parameters.
V
OUT(max) = 1.05 V
R
OUT = -1.0 mΩ
I
MAX = 40 A
I
DYN = 30 A
Slew rate = 5.0 mV/s (minimum)
The TPS51727 architecture is designed to work with a load line defined by ROUT. The output voltage drops by an
accurately defined amount as the output current increases. The minimum supported load-line is –1.0m
.
Step Two
Determine system parameters. The input voltage range and operating frequency are of primary interest. For
example:
1. VIN(max) = 15 V
2. VIN(min) = 8 V
3. f = 300 kHz
Step Three
Determine current sensing method. The TPS51727 supports both resistor sensing and inductor DCR sensing.
Inductor DCR sensing is chosen. For resistor sensing, substitute the resistor value (1 m
recommended for a
40-A application) for RCS in the subsequent equations and skip Step Four.
Step Four
Determine inductor value and choose inductor. Smaller values of inductor have better transient performance but
higher ripple and lower efficiency. Higher values have the opposite characteristics. It is common practice to limit
the ripple current to 30% to 50% of the maximum current per phase. In this case, use 40%.
At f = 300 kHz, with a 15-V input and a 1.05-V output:
where
V = V
IN(max) – VOUT(max)
LMAX = 0.406 H
28
Copyright 2008–2009, Texas Instruments Incorporated
Product Folder Link(s): TPS51727
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