参数资料
型号: ADP1829ACPZ-R7
厂商: Analog Devices Inc
文件页数: 21/28页
文件大小: 0K
描述: IC REG CTRLR BUCK PWM VM 32LFCSP
标准包装: 1
PWM 型: 电压模式
输出数: 2
频率 - 最大: 720kHz
占空比: 93%
电源电压: 3 V ~ 20 V
降压:
升压:
回扫:
反相:
倍增器:
除法器:
Cuk:
隔离:
工作温度: -40°C ~ 125°C
封装/外壳: 32-VFQFN 裸露焊盘,CSP
包装: 标准包装
产品目录页面: 791 (CN2011-ZH PDF)
配用: ADP1829-EVALZ-ND - BOARD EVALUATION ADP1829
其它名称: ADP1829ACPZ-R7DKR
Data Sheet
Type II Compensator
ADP1829
Next choose the high frequency pole, f P1 , to be 1/2 of f SW .
f P1 ?
G
(dB)
PHASE
–1
S
LO
PE
f Z
f P
–1
S
LO
PE
1
f SW
2
Because C HF << C I , Equation 29 is simplified to
(36)
–180°
–270°
f P1 ?
1
2 ? R Z C HF
(37)
C HF
Solving for C HF in Equation 36 and Equation 37 yields
C HF ?
FROM
V OUT
R TOP
R BOT
R Z
EA
C I
COMP
TO PWM
1
? f SW R Z
Type III Compensator
(38)
VREF
VRAMP
0V
Figure 28. Type II Compensation
G
(dB)
–1
S
LO
PE
+1
S
LO
PE
–1
SL
O
PE
If the output capacitor ESR zero frequency is sufficiently low (≤1/2
of the crossover frequency), use the ESR to stabilize the
regulator. In this case, use the circuit shown in Figure 28.
Calculate the compensation resistor, R Z , with the following
–90°
PHASE
–270°
f Z
C HF
f P
equation:
R FF
C FF
R Z
C I
V IN f LC
R Z ?
R TOP V RAMP f ESR f CO
2
(31)
FROM
V OUT
R TOP
R BOT
EA
COMP
TO PWM
where:
f CO is chosen to be 1/10 of f SW .
V RAMP is 1.3 V.
VREF
0V
Figure 29. Type III Compensation
VRAMP
f Z 1 ?
?
?
f Z 1 ?
?
f P1 ? f P2 ?
f Z1 ? f Z2 ?
?
?
f CO f SW 1
Next choose the compensation capacitor to set the
compensation zero, f Z1 , to the lesser of 1/4 of the crossover
frequency or 1/2 of the LC resonant frequency:
f CO f SW 1
4 40 2 ? R Z C I
or
f LC 1
2 2 ? R Z C I
Solving for C I in Equation 32 yields
(32)
(33)
If the output capacitor ESR zero frequency is greater than 1/2 of
the crossover frequency, use Type III compensator as shown in
Figure 29. Set the poles and zeros as follows:
1
f SW (39)
2
(40)
4 40 2 ? R Z C I
or
C I ?
20
? R Z f SW
(34)
f Z 1 ? f Z 2 ?
f LC
2
?
1
2 ? R Z C I
(41)
C I ?
R Z ?
R TOP V RAMP f Z1 f CO
Solving for C I in Equation 33 yields
1
? R Z f LC
Use the larger value of C I from Equation 34 or Equation 35.
(35)
Use the lower zero frequency from Equation 40 or Equation 41.
Calculate the compensator resistor, R Z .
(42)
V IN f LC 2
Because of the finite output current drive of the error amplifier,
Next calculate C I .
C I needs to be less than 10 nF. If it is larger than 10 nF, choose a
larger R TOP and recalculate R Z and C I until C I is less than 10 nF.
C I ?
1
2 π R Z f Z1
(43)
Rev. C | Page 21 of 28
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