参数资料
| 型号： | EVAL-ADE7763ZEB |
| 厂商： | Analog Devices Inc |
| 文件页数： | 25/56页 |
| 文件大小： | 0K |
| 描述： | BOARD EVALUATION FOR ADE7763 |
| 标准包装： | 1 |
| 主要目的： | 电源管理，电度表/功率表 |
| 已用 IC / 零件： | ADE7763 |
| 已供物品： | 板 |
| 相关产品： | ADE7763ARSZRLDKR-ND - IC ENERGY METERING 1PHASE 20SSOP ADE7763ARSZRLCT-ND - IC ENERGY METERING 1PHASE 20SSOP ADE7763ARSZ-ND - IC ENERGY METERING 1PHASE 20SSOP ADE7763ARSZRLTR-ND - IC ENERGY METERING 1PHASE 20SSOP |
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Data Sheet
As seen from the plots, the phase response is almost 0 from
45 Hz to 1 kHz, which is all that is required in typical energy
measurement applications. However, despite being internally
phase-compensated, the ADE7763 must work with transducers,
which could have inherent phase errors. For example, a phase
error of 0.1° to 0.3° is not uncommon for a current transformer
(CT). Phase errors can vary from part to part and must be
corrected in order to perform accurate power calculations. The
0.9
0.8
0.7
0.6
0.5
0.4
0.3
0.2
ADE7763
errors associated with phase mismatch are particularly
noticeable at low power factors. The ADE7763 provides a
means of digitally calibrating these small phase errors by
allowing a short time delay or time advance to be introduced
0.1
0
–0.1
10 2
10 3
10 4
into the signal processing chain to compensate for these errors.
Because the compensation is in time, this technique should only
be used for small phase errors in the range of 0.1° to 0.5°.
Correcting large phase errors using a time shift technique can
introduce significant phase errors at higher harmonics.
The phase calibration register (PHCAL[5:0]) is a twos comple-
ment, signed, single-byte register that has values ranging from
0x21 (–31d) to 0x1F (+31d).
The register is centered at 0Dh, so that writing 0Dh to the register
produces 0 delay. By changing the PHCAL register, the time
delay in the Channel 2 signal path can change from –102.12 μs
to +39.96 μs (CLKIN = 3.579545 MHz). One LSB is equivalent
to 2.22 μs (CLKIN/8) time delay or advance. A line frequency of
60 Hz gives a phase resolution of 0.048° at the fundamental (i.e.,
0.20
0.18
0.16
0.14
0.12
0.10
0.08
0.06
0.04
0.02
FREQUENCY (Hz)
Figure 50. Combined Phase Response of HPF and
Phase Compensation (10 Hz to 1 kHz)
360° × 2.22 μs × 60 Hz). Figure 49 illustrates how the phase
compensation is used to remove a 0.1° phase lead in Channel 1
due to the external transducer. To cancel the lead (0.1°) in
Channel 1, a phase lead must also be introduced into Channel 2.
The resolution of the phase adjustment allows the introduction
of a phase lead in increments of 0.048°. The phase lead is
achieved by introducing a time advance in Channel 2. A time
advance of 4.44 μs is made by writing ?2 (0x0B) to the time delay
block, thus reducing the amount of time delay by 4.44 μs, or
equivalently, a phase lead of approximately 0.1° at line frequency
of 60 Hz. 0x0B represents –2 because the register is centered
with 0 at 0Dh.
V1P
HPF
0
40
0.4
0.3
0.2
0.1
0.0
–0.1
45 50 55 60 65
FREQUENCY (Hz)
Figure 51. Combined Phase Response of HPF and
Phase Compensation (40 Hz to 70 Hz)
70
V1
PGA1
ADC 1
24
–0.2
V1N
24
LPF2
–0.3
V2
V2P
V2N
PGA2
V2
ADC 2
1
DELAY BLOCK
2.22 μ s/LSB
5
0 0 1 0 1 1
0
CHANNEL 2 DELAY
REDUCED BY 4.44 μ s
(0.1°LEAD AT 60Hz)
0x0B IN PHCAL [5.0]
V2
V1
–0.4
54 56 58 60 62 64 66
FREQUENCY (Hz)
Figure 52. Combined Gain Response of HPF and Phase Compensation
ACTIVE POWER CALCULATION
V1
0.1°
PHCAL[5:0]
–102.12 μ s TO +39.96 μ s
Power is defined as the rate of energy flow from the source to
the load. It is defined as the product of the voltage and current
60Hz
Figure 49. Phase Calibration
60Hz
waveforms. The resulting waveform is called the instantaneous
power signal and is equal to the rate of energy flow at any given
time. The unit of power is the watt or joules/s. Equation 9 gives
an expression for the instantaneous power signal in an ac system.
Rev. C | Page 25 of 56
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