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| 型号： | ADE7753ARSZ |
| 厂商： | Analog Devices Inc |
| 文件页数： | 28/60页 |
| 文件大小： | 0K |
| 描述： | IC ENERGY METERING 1PHASE 20SSOP |
| 标准包装： | 66 |
| 输入阻抗： | 390 千欧 |
| 测量误差： | 0.1% |
| 电压 - 高输入/输出： | 2.4V |
| 电压 - 低输入/输出： | 0.8V |
| 电流 - 电源： | 3mA |
| 电源电压： | 4.75 V ~ 5.25 V |
| 测量仪表类型： | 单相 |
| 工作温度： | -40°C ~ 85°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 20-SSOP（0.209"，5.30mm 宽） |
| 供应商设备封装： | 20-SSOP |
| 包装： | 管件 |
| 产品目录页面： | 797 (CN2011-ZH PDF) |
| 配用： | EVAL-ADE7753ZEB-ND - BOARD EVALUATION AD7753 |
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ADE7753
0.4
0.3
0.2
the current and voltage signals. The dc component of the
instantaneous power signal is then extracted by LPF2 (low-pass
filter) to obtain the active power information. This process is
0.1
0.0
–0.1
–0.2
0x19999A
VI
INSTANTANEOUS
POWER SIGNAL
p(t) = v × i-v × i × cos(2 ω t)
ACTIVE REAL POWER
SIGNAL = v × i
0xCCCCD
–0.3
–0.4
54
56
58
60 62
FREQUENCY (Hz)
64
66
0x00000
02875-0-059
Figure 60. Combined Gain Response of the HPF and Phase Compensation
ACTIVE POWER CALCULATION
Power is defined as the rate of energy flow from source to load.
CURRENT
i(t) = 2 × i × sin( ω t)
VOLTAGE
v(t) = 2 × v × sin( ω t)
It is defined as the product of the voltage and current wave-
forms. The resulting waveform is called the instantaneous
Figure 61. Active Power Calculation
02875-0-060
power signal and is equal to the rate of energy flow at every
instant of time. The unit of power is the watt or joules/sec.
Equation 9 gives an expression for the instantaneous power
signal in an ac system.
Since LPF2 does not have an ideal “brick wall” frequency
response—see Figure 62, the active power signal has some
ripple due to the instantaneous power signal. This ripple is
sinusoidal and has a frequency equal to twice the line frequency.
v ( t ) =
i ( t ) =
where:
2 × V sin( ω t )
2 × I sin( ω t )
(7)
(8)
Because the ripple is sinusoidal in nature, it is removed when
the active power signal is integrated to calculate energy—see the
Energy Calculation section.
0
V is the rms voltage.
I is the rms current.
–4
p ( t ) = v ( t ) × i ( t )
p ( t ) = VI ? VI cos( 2 ω t )
(9)
–8
The average power over an integral number of line cycles (n) is
given by the expression in Equation 10.
–12
∫ 0
P =
1
nT
nT
p ( t ) dt = VI
(10)
–16
–20
where:
T is the line cycle period.
P is referred to as the active or real power.
Note that the active power is equal to the dc component of the
instantaneous power signal p(t) in Equation 8, i.e., VI. This is
–24
1
3 10 30
FREQUENCY (Hz)
Figure 62. Frequency Response of LPF2
100
02875-0-061
the relationship used to calculate active power in the ADE7753.
The instantaneous power signal p(t) is generated by multiplying
Rev. C | Page 28 of 60
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相关代理商/技术参数 |
参数描述 |
|---|---|
| ADE7753ARSZ | 制造商:Analog Devices 功能描述:ENERGY METERING IC |
| ADE7753ARSZ | 制造商:Analog Devices 功能描述:IC MULTIFUNCTION METER |
| ADE7753ARSZRL | 功能描述:IC ENERGY METERING 1PHASE 20SSOP RoHS:是 类别:集成电路 (IC) >> PMIC - 能量测量 系列:- 产品培训模块:Lead (SnPb) Finish for COTS Obsolescence Mitigation Program 标准包装:2,500 系列:* |
| ADE7753-ARSZRL | 制造商:Analog Devices 功能描述: |
| ADE7753XRS | 制造商:Analog Devices 功能描述: |
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